Quantitative Aptitude - Data Interpretation Questions

What is Quantitative Aptitude- Data Interpretation?

Data Interpretation is the process of analysing data, inspecting the elements in data and Interpreting to extract maximum information from the given set of data or information. The data is given in the form of charts, tables and graphs. Data Interpretation has no particular syllabus, this section tests one's ability in analysing data, decision making capability and speed. Data Interpretation looks simple and easy but the calculations are time consuming. For solving the data interpretation problems efficiently one should analyse the given data and focus on aspects of the data that are necessary to answer the questions, before attending data interpretation section one should be very comfortable with numbers, calculations, percentages, fractions, averages and ratios to increase the calculation speed.

We come across Data Interpretation Questions in many competitive exams and Entrance Tests like Bank Exams (SBI PO), MBA entrance exams (CAT, MAT), HPAS, APPSC group1, HR executives, UPSC CPF (AC),IBPS ,UP Police constable exams, TNPSC VAO, WBSC, PPSC, HAL Results, NDA, Lokhsabha secretariat, Rajyasabha secretariat exams and more

Thorough practice of different papers on data interpretation allows you to solve different kinds of data interpretation and can help improve your logic in solving problems.

We have a large database of questions on Quantitative Aptitude (Data Interpretation) for you to practice and score high.

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Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies ove the Years (Number in Thousands)

1. What is the difference between the number of vehicles manufactured by Company Y in 2000 and 2001 ?

A. 50000 B. 42000 C. 33000 D. 21000

2. What is the difference between the total productions of the two Companies in the given years ?

A. 19000 B. 22000 C. 26000 D. 28000

3. What is the average numbers of vehicles manufactured by Company X over the given period ? (rounded off to nearest integer)

A. 119333 B. 113666 C. 112778 D. 111223

4. In which of the following years, the difference between the productions of Companies X and Y was the maximum among the given years ?

A. 1997 B. 1998 C. 1999 D. 2000

5. The production of Company Y in 2000 was approximately what percent of the production of Company X in the same year ?

A. 173 B. 164 C. 132 D. 97

Answer

1. ANSWERS : D

Explanation- Required difference = (128000 - 107000) = 21000.

2. ANSWERS : C

Explanation- From the line-graph it is clear that the productions of Company X in the years 1997, 1998, 1999, 2000, 2001 and 2002 are 119000, 99000, 141000, 78000, 120000 and 159000 and those of Company Y are 139000, 120000,100000, 128000, 107000 and 148000 respectively.

Total production of Company X from 1997 to 2002

= 119000 + 99000 + 141000 + 78000 + 120000 + 159000

= 716000.

and total production of Company Y from 1997 to 2002

= 139000 + 120000 + 100000 + 128000 + 107000 + 148000

= 742000.

Difference = (742000 - 716000) = 26000.

3. ANSWERS : A

Explanation- Average number of vehicles manufactured by Company X

= $\frac{1}{6} \times (119000 + 99000 + 141000 + 78000 + 120000 + 159000)$

= 119333.

4. ANSWERS : D

Explanation- The difference between the productions of Companies X and Y in various years are:

For 1997 (139000 - 119000) = 20000.

For 1998 (120000 - 99000) = 21000.

For 1999 (141000 - 100000) = 41000.

For 2000 (128000 - 78000) = 50000.

For 2001 (120000 - 107000) = 13000.

For 2002 (159000 - 148000) = 11000.

Clearly, maximum difference was in 2000.

5. ANSWERS : B

Explanation - Required percentage= $\frac{128000}{78000} \times 100$ % = 164%

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Subject: Line Charts - Quantitative Aptitude - Data Interpretation

22 7851

DI.

What is the difference between the number of uneducated females in city P and that of uneducated males in city S ?

A) 9 lakhs	B) 6 lakhs
C) 3 lakhs	D) 2 lakhs

Answer & Explanation Answer: A) 9 lakhs

Explanation:

Educated females in city P = 25 lakhs

Uneducated females in city P = 30 - 25 = 5 lakhs

Educated males city S = 21 lakhs

Educated males in city S = 35 - 21= 14 lakhs

Required difference = 14 - 5 = 9 lakhs

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Filed Under: Table Charts - Quantitative Aptitude - Data Interpretation
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

13 2054

Study the following graph carefully and answer the questions that follow:

Water level of four major Rivers (in meters) in four different Months

1. what was the respective ratio between the level of River - C in September and the water level of River - B in June?

1. 91 : 101 2. 94 : 101 3. 51 : 103 4. None of these

2. If the danger level of all the four rivers is above 215 m, which river has not crossed the danger level in August but has crossed the danger level in July ?

1. River - A 2. River - B 3. River - C 4. River - D

3. What is the average water level of River - A in all the four months together ?

1. 224.50 m 2. 212.25 m 3. 210.75 m 4. 222.25 m

4. In which river and in which month respectively the water level is highest ?

1. River - C in August 2. River - D in September 3. River - B in July 4. River - D in August

5. If the water level of River - A in July is decreased by 20 percent, then what will be the water level of River - A in July ?

1. 156 m 2. 162 m 3. 164 m 4. 152 m

Answer

1. Answer : 4

Explanation : The water level of River-C in September = 184 and water level of River-B in June = 202

Required ratio = 184 : 202 => 92 : 101

2. Answer : 2

3. Answer : 3

Explanation : Average water level of River-A in all months = $\frac{196 + 205 + 230 + 212}{4}$ = 210.75 m

4. Answer : 4

5. Answer : 3

Explanation : Water level of River-A in July after decreasing = $205 \times \frac{80}{100}$ = 41 x 4 = 164m

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Subject: Bar Charts - Quantitative Aptitude - Data Interpretation

13 8140

The following bar graph indicates the production of sugar (in lakh tonnes) by three different sugar companies P, Q and R over years 2009 to 2013.

Production of Sugar by Companies P, Q and R during 2009 - 2013

1. The percentage increase in production of Company Q from the year 2009 to the year 2013 is :

1. 80% 2. 90% 3. 60% 4. 100%

2. The average production over the years 2009 - 2013 was maximum for the Company(ies):

1. Q 2. P 3. R 4. P and R

3. The percentage rise or fall in production of Company Q as compared to the previous year is the maximum in the year :

1. 2011 2. 2010 3. 2013 4. 2012

4. The percentage of production of Company R to Production of Company Q is the maximum in the year

1. 2010 2. 2009 3. 2011 4. None of these

5. The ratio of the average production of Company P during the years 2011 to 2013 to the average production of Company Q for the same period is :

1. 23 : 25 2. 27 : 29 3. 15 : 17 4. 9 : 11

Answer

1. Answer : 4

Explanation : Required Percentage = $\frac{100 - 50}{50} \times 100$ = 100%

2. Answer : 4

Explanation : The average production of P = $\frac{60 + 90 + 50 + 100 + 80}{5}$ = 76

The average production of Q = $\frac{50 + 70 + 70 + 80 + 100}{5}$ = 74

The average production of R = $\frac{70 + 80 + 90 + 70 + 70}{5}$ = 76

Maximum average production = P and R both

3. Answer : 2

Explanation : The percentage rise in 2010 = $\frac{70 - 50}{50} \times 100$ = 40%

The percentage rise in 2011 = $\frac{70 - 70}{70} \times 100$ = 0%

The percentage rise in 2012 = $\frac{80 - 70}{70} \times 100$ = 14.28%

The percentage rise in 2013 = $\frac{100 - 80}{80} \times 100$ =25%

4. Answer : 2

Explanation : The percentage of production of Company R to production of Company Q

in 2009 = $\frac{70}{50} \times 100$ = 140

in 2010 = $\frac{80}{70} \times 100$ = 114.28

in 2011 = $\frac{90}{70} \times 100$ = 128.57

in 2012 = $\frac{70}{80} \times 100$ = 87.5

in 2013 = $\frac{70}{100} \times 100$ = 70

5. Answer : 1

Explanation : Average production of company P during the years 2011 to 2013 = $\frac{50 + 100 + 80}{3}$ = $\frac{230}{3}$

Average production of company Q during the years 2011 to 2013 = $\frac{70 + 80 + 100}{3}$ = $\frac{250}{3}$

Required ratio = 23 : 25

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Subject: Bar Charts - Quantitative Aptitude - Data Interpretation

13 4119

Study the following pie-charts to answer the following questions :

The pie-charts show the expenditure of two companies A and B, Which are Rs.50 lakh and Rs.60 lakh respectively.

1.If the incomes of Company A and B are in the ratio of 4:5 and the income of Company B is 180% of its expenditure,then what is the difference between the income of Company B and the income of Company A ?

1.Rs.2200000 2. Rs.1900000 3. Rs.2160000 4. Rs.1850000 5.Rs.2250000

2.If the number of employees in Company A is a hundred then what is the average salary of the employees in Company A ?

1. Rs.14000 2. Rs.16000 3. Rs.13000 4. Rs.15000 5. Rs.15500

3.What is the ratio of tax paid by Company A to that by Company B ?

1. 35:18 2. 34:37 3. 42:41 4. 31:27 5. 27:25

4.What is the difference between the expenditure on employees of Company B and that of Company A?

1.Rs.4300000 2. Rs.6400000 3. Rs.5900000 4. Rs.8700000 5.Rs.7800000

5.The expenditure on Machine and Electricity of Company B is what per cent more than that on the same item of Company A?

1. 67% 2. 84% 3. 75% 4. 77% 5. 80%

Answer

1. Answer : 3

Explanation : Expenditure of Company B = 60 lakh

Income of Company B = $60 \times \frac{180}{100}$ = 108 lakh = 1 crore 8 lakh

Income of Company A = $10800000 \times \frac{4}{5}$ = Rs. 8640000

Therefore, Required differeence = 10800000 - 8640000 = Rs.2160000

2. Answer : 1

Explanation : Total expenditure on the employees of company A = $5000000 \times \frac{28}{100}$ = Rs.1400000

Average Salary of the employees = $\frac{1400000}{100}$ = Rs.14000

3. Answer : 1

Explanation : Tax paid by Company A : Tax paid by Company B

= $5000000 \times \frac{14}{100}$ : $6000000 \times \frac{6}{100}$

= 700000 : 3600000 = 35 : 18

4. Answer : 2

Explanation : Difference = $6000000 \times \frac{34}{100} - 5000000 \times \frac{28}{100}$

= 2040000 - 1400000 = Rs.640000

5. Answer : 5

Explanation : Expenditure on Machine and Electricity of Company B = $6000000 \times \frac{18}{100}$ = Rs.1080000 = 10.8 lakh

Expenditure on Machine and Electricity of Company A = $5000000 \times \frac{12}{100}$ = Rs.600000 = 6 lakh

Therefore, Required % = $\frac{1080000 - 600000}{600000} \times 100$ % = $\frac{48}{60} \times 100$ % = 80%

Hence expenditure of Company B is 80% more than Company A.

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Subject: Pie Charts - Quantitative Aptitude - Data Interpretation

12 5102

Study the pie - chart carefully to answer the questions below :

The Pie chart shows the percentage quantity of fruits at two fruit shops A and B

1. What is the difference between the quantity of Guava at Shop B and that at Shop A ?

1. 40 Kg 2. 45 kg 3. 35 kg 4. 30 kg 5. 50 kg

2. If the price of Mango is Rs. 30 per kg, Apple Rs.40 per kg and orange Rs.20 per kg, then what is the ratio of their costs at Shop A?

1. 1 : 4 : 6 2. 9 : 8 : 5 3. 3 : 7 : 8 4. 5 : 4 : 1 5. 2 : 5 : 7

3. The quantity of Mango at Shop B is what per cent of the quantity of Mango at Shop A ?

1. 20% 2. 220% 3. 120% 4. 80% 5. 180%

4. If the price of Mango is Rs.30 per kg, Apple Rs. 40 per kg, orange Rs.20 per kg, Other fruits Rs.15 per kg and Guava Rs. 18 per kg for both Shop A and B, then what is the difference between the cost of all fruits at Shop A and that at Shop B ?

1. Rs.7200 2. Rs.3500 3. Rs. 6400 4. Rs.5100 5. Rs.4600

5. The quantity of Orange at Shop A is what percent more than that of Apple at Shop B ?

1. 161.52% 2. 195.5% 3. 182% 4. 190% 5. 171.42%

Answer

1. Answer : 1

Explanation : Quantity of Guava at Shop A = $1200 \times \frac{10}{100}$ = 120 kg

Quantity of Guava at Shop B = $1000 \times \frac{16}{100}$ = 160 kg

Therefore, Required difference = 160 - 120 = 40 kg

2. Answer : 2

Explanation : Cost of Mango at Shop A = $30 \times 1200 \times \frac{24}{100}$ = Rs. 8640

Cost of Apple = $40 \times 1200 \times \frac{16}{100}$ = Rs. 7680

Cost of Orange = $20 \times 1200 \times \frac{20}{100}$ = Rs.4800

Therefore, Required Ratio = 8640 : 6780 : 4800 = 9 : 8 : 5

3. Answer : 3

Explanation : Quantity of Mango at Shop B = $1000 \times \frac{24}{100}$ = 240 kg

Quantity of Mango at Shop A = $1200 \times \frac{24}{100}$ = 288 kg

Therefore, Req % = $288 \times \frac{100}{240}$ = 120% of the quantity of Mango at Shop A

4. Answer : 4

Explanation : Cost of total fruits at Shop A = Cost of Mango + Cost of Apple + Cost of Guava + Cost of orange + Cost of other fruits

= $1200 \times \frac{24}{100} \times 30 + 1200 \times \frac{16}{100} \times 40 + 1200 \times \frac{10}{100} \times 18 + 1200 \times \frac{20}{100} \times 20 + 1200 \times \frac{30}{100} \times 15$

= Rs. 28680

Cost of Total Fruits at Shop B

= $1000 \times \frac{24}{100} \times 30 + 1000 \times \frac{14}{100} \times 40 + 1000 \times \frac{16}{100} \times 18 + 1000 \times \frac{20}{100} \times 20 + 1000 \times \frac{26}{100} \times 15$

= 7200 + 5600 + 2880 + 4000 + 3900

= Rs. 23580

Therefore, Req.difference = 28680 - 23580 = Rs.5100

5. Answer : 5

Explanation: Quantity of Orange at Shop A = $1200 \times \frac{20}{100}$ = 240 kg

Quantity of Apple at Shop B = $1000 \times \frac{14}{100}$ = 140 kg

Therefore, Req % = $\frac{240 \times 100}{140}$ = 171.42% more than the quantity of Apple at Shop B.

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Subject: Pie Charts - Quantitative Aptitude - Data Interpretation

11 7702

The pie chart drawn below shows below the spendings of a country on various sports during a particular year. Study the pie chart and answer the questions.

If the total amount spent on sports during the year was Rs. 1,20,00,000 how muchwas spent on basketball

A) Rs. 950000	B) Rs. 10,00,000
C) Rs. 12,00,000	D) Rs. 15,00,000

Answer & Explanation Answer: D) Rs. 15,00,000

Explanation:

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Exam Prep: Bank Exams

10 2437

A train runs through cities A, B, C, D, E, F, G and H. The line graph indicates the time schedule of the train including times of arrival and departure.

1. The total stoppage time at the cities in the first half and second half of the total distance is in the ratio.

1. 1 : 3 2. 3 : 1 3. 2 : 1 4. 1 : 2

2. Between how many pairs of consecutive stations does the speed run below the overall average speed of the entire trip?

1. 2 2. 1 3. 3 4. 4

3. If the train stops at each city for 50% more time than what it is at present, then at what time will it arrive at city H after departing from city A as per schedule ?

1. 20.16 2. 19.02 3. 18.51 4. 18.59

4. The overall average speed of the entire trip excluding stoppage time is nearly :

1. 75 km/h 2. 81 km/h 3. 46 km/h 4. 65 km/hr

5. What percent of time of the entire trip was actually spent travelling between the cities ?

1. 91.8% 2. 7.6% 3. 76% 4. 24%

Answer

1. Answer : 4

Explanation : Required ratio = $\frac{10 + 2 + 5}{10 + 15 + 10} = \frac{17}{35} \approx \frac{1}{2} = 1 : 2$

2. Answer : 1

Explanation :

A to B Speed = $\frac{140 \times 3}{5}$ = 84

B to C Speed = $\frac{91 \times 3}{4}$ = 68.25

C to D Speed = $\frac{149 \times 60}{103}$ = 86.796

D to E Speed = $\frac{88 \times 3}{4}$ = 66

E to F Speed = $\frac{106 \times 4}{5}$ = 84.8

F to G Speed = $\frac{176}{2}$ = 88

G to h Speed = $\frac{110 \times 4}{5}$ = 88

Average speed of entire trip = $\frac{84 + 68.25 + 86.796 + 66 + 84.8 + 88 + 88}{7}$ =80.83

3. Answer : 3

Explanation : Total half time = 10 + 2 + 5 + 10 + 15 + 10 = 52

Total half time, if the train stops at each city for 50% more= $52 \times \frac{150}{100}$ =78

Train will arrive at city H after departing from city A = 18.25 + (78 - 52 )=18.25 + 26=18.51

4. Answer : 2

Explanation : Average speed = $\frac{84 + 68.25 + 86.796 + 66 + 84.8 + 88 + 88}{7}$ =80.83=81 km/hr

5. Answer : 1

Explanation : Required percentage of time = $\frac{1.40 + 1.20 + 1.43 + 1.20 + 1.15 + 2 + 1.15}{18.25 - 7} \times 100$ = $\frac{10.23}{11.25} \times 100$ = 91.8 %

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Subject: Line Charts - Quantitative Aptitude - Data Interpretation

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