Quantitative Aptitude - Data Interpretation Questions

What is Quantitative Aptitude- Data Interpretation?

Data Interpretation is the process of analysing data, inspecting the elements in data and Interpreting to extract maximum information from the given set of data or information. The data is given in the form of charts, tables and graphs. Data Interpretation has no particular syllabus, this section tests one's ability in analysing data, decision making capability and speed. Data Interpretation looks simple and easy but the calculations are time consuming. For solving the data interpretation problems efficiently one should analyse the given data and focus on aspects of the data that are necessary to answer the questions, before attending data interpretation section one should be very comfortable with numbers, calculations, percentages, fractions, averages and ratios to increase the calculation speed.

We come across Data Interpretation Questions in many competitive exams and Entrance Tests like Bank Exams (SBI PO), MBA entrance exams (CAT, MAT), HPAS, APPSC group1, HR executives, UPSC CPF (AC),IBPS ,UP Police constable exams, TNPSC VAO, WBSC, PPSC, HAL Results, NDA, Lokhsabha secretariat, Rajyasabha secretariat exams and more

Thorough practice of different papers on data interpretation allows you to solve different kinds of data interpretation and can help improve your logic in solving problems.

We have a large database of questions on Quantitative Aptitude (Data Interpretation) for you to practice and score high.

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Study the given bar graph and pie chart to answer the following questions.

The bar graph shows the production (in thousand tonnes) of Wheat, Rice and Maize in different states.

The pie-chart shows the percentage of agricultural land in the given six states.

Productivity = $\frac{Total\: Production}{Area\: of\: agricultural\: land}$

1.The productivity of which state is the maximum ?

1. Bihar 2. Haryana 3. Punjab 4. UP 5. MP

2.The production of which state is the maximum ?

1. Bihar 2. MP 3. Haryana 4. UP 5. Punjab

3.The prodution of wheat in punjab is what per cent more than the production of Maize in odisha ?

1. 350% 2. 250% 3. 300% 4. 200% 5. 400%

4.What is the ratio of the production of Rice in Bihar to the production of Wheat in Haryana ?

1. 2:3 2. 3:2 3. 2:1 4. 1:1 5. 1:2

5.If MP exports 40% of Rice at the rate of Rs.30 per kg and UP exports 30% of Rice at the rate of Rs.32 per kg, then what is the ratio of the income from the exports ?

1. 65:48 2. 31:42 3. 43:54 4. 57:62 5. 1:2

Answer

1. Answer : 2

Explanation : Productivity = Total production/area of Agr.land

Productivity of UP = [ (35000+30000+25000) / (30/100) ] = 300000

Productivity of MP = [ (30000+37500+27500) / (25/100) ] = 380000

Productivity of Bihar = [ (22500+27500+25000) / (20/100) ] = 375000

Productivity of Odisha = [ (22500+15000+10000) / (5/100) ]= 950000

Productivity of Haryana = [ (30000+25000+35000) / (8/100) ] = 1125000

Productivity of Punjab = [ (40000+35000+30000) / (12/100) ] = 875000

The Productivity of Haryana is the maximum.

2. Answer : 5

Explanation : Production of Punjab is maximum = 105000 tonnes

3. Answer : 3

Explanation : Production of Wheat in Punjab = 40000 tones

Production of Maize in Odisha = 10000 tones

Required % = (40000 - 10000)/100 = 300%

4. Answer : 4

Explanation : The ratio of prodution of Rice in Bihar to the production of Wheat in Haryana = 25000 tonnes : 25000 tonnes = 1 : 1

5. Answer : 1

Explanation : Income of MP from export of 40% of Rice at the rate of Rs.30 per kg = Rs.39crore

Income of UP from export of 30% of Rice at the rate of Rs.32 per kg = Rs.28.8 crore

Required ratio = 39 : 28.8 = 390 : 288 = 65 : 48

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Subject: Bar Charts - Quantitative Aptitude - Data Interpretation Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

118 26657

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

2. How many students are there in Class IX in the school?

A. 336 B.189 C. 335 D. 430

3. Which section has the maximum pass percentage in at least one of the two examinations?

A. A Section B. B Section C. C Section D. D Section

4. Which section has the maximum success rate in annual examination?

A. A Section B. B Section C. C Section D. D Section

5. Which section has the minimum failure rate in half yearly examination?

A. A section B. B section C. C section D. D section

Half yearly examinations were more difficult.

If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C

Explanation - Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

2. ANSWER : D

Explanation - Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

3. ANSWER : D

Explanation- Pass percentages in at least one of the two examinations for different sections are:

For Section A = $\frac{14 + 6 + 64}{28 + 14 + 6 + 64} \times 100 = \frac{84}{112} \times 100$ % = 75%

For Section B = $\frac{12 + 17 + 55}{23 + 12 + 17 + 55} \times 100$ % = 78.5%

For Section C = $\frac{8 + 9 + 46}{17 + 8 + 9 + 46} \times 100$ %= 78.75%

For Section D = $\frac{13 + 15 + 76}{27 + 13 + 15 + 76} \times 100$ %= 79.39%

Clearly ,the pass percentage is maximum for Section D

4. ANSWER : A

Explanation - Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

Success rate in annual exams in Section A= $\frac{14 + 64}{112} \times 100$ % = 69.64%

Similarly, success rate in annual exams in:

Section B = $\frac{12 + 55}{107} \times 100$ % = 62.62%

Section C = $\frac{8 + 46}{80} \times 100$ % = 67.5%

Section D = $\frac{89}{131} \times 100$ % = 67.94%

Clearly, the success rate in annual examination is maximum for Section A.

5. ANSWER : D

Explanation - Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section

Failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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Subject: Table Charts - Quantitative Aptitude - Data Interpretation Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

72 26227

Study the following table and answer the questions based on it. Expenditures of a Company (in Pesetas) per Annum Over the given Years.

1. What is the average amount of interest per year which the company had to pay during this period?

A. 32.43 B. 33.72 C. 34.18 D. 36.66

2. The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?

A. 0.1% B. 0.5% C. 1.0% D. 1.25 %

3. Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?

A. 62% B. 66% C. 69% D. 71%

4. The total expenditure of the company over these items during the year 2000 is?

A. 544.44 B. 501.11 C. 446.46 D. 478.87

5. The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?

A. 4 : 7 B. 10 : 13 C. 15 : 18 D. 5 : 8

The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

The total expenditure of the company over these items during the year 2000 is? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

0.1%

What is the average amount of interest per year which the company had to pay during this period? - See more at: https://www.theonlinetestcentre.com/table-charts.html#1

Answer

1. ANSWER : D

Explanation -

Average amount of interest paid by the company during the given period

= $R s . \frac{23.4 + 32.5 + 41.6 + 36.4 + 49.4}{5} l a k h s = R s . \frac{183.3}{5} l a k h s$

= Rs. 36.66 lakhs

2. ANSWER : C

Explanation -

Required Percentage = $\frac{3.00 + 2.52 + 3.84 + 3.68 + 3.96}{288 + 342 + 324 + 336 + 420} \times 100$ %

= $\frac{17}{1710} \times 100$ % $\approx$ 1%

3. ANSWER: C

Explanation -

Required Percentage = $\frac{288 + 98 + 3.00 + 23.4 + 83}{420 + 142 + 3.96 + 49.4 + 98} \times 100$

= $\frac{495.4}{713.36} \times 100$ $\approx$ 69.45%

4. ANSWER: A

Explanation - Total expenditure of the Company during 2000 = (324 + 101 + 3.84 + 41.6 + 74) lakhs = 544.44 lakhs

5. ANSWER : B

Explanation -

Required ratio = $\frac{83 + 108 + 74 + 88 + 98}{98 + 112 + 101 + 133 + 142}$

= $\frac{451}{586}$

= $\frac{1}{1.3} = \frac{10}{13}$

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Subject: Table Charts - Quantitative Aptitude - Data Interpretation

46 17985

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

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Subject: Table Charts - Quantitative Aptitude - Data Interpretation

28 11930

Study the following graph carefully and answer the questions given below:

Distribution of candidates who were enrolled for MBA entrance exam and the candidates (out of those enrolled) who passed the exam in different institutes:

1. What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?

A. 50% B. 62.5% C. 75% D. 80%

2. Which institute has the highest percentage of candidates passed to the candidates enrolled?

A. Q B. R C. V D. T

3. The number of candidates passed from institutes S and P together exceeds the number of candidates enrolled from institutes T and R together by:

A. 228 B. 279 C. 399 D. 407

4. What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?

A. 68% B. 80% C. 74% D. 65%

5. What is the ratio of candidates passed to the candidates enrolled from institute P?

A. 9:11 B. 14:17 C. 6:11 D. 9:17

Answer

1. ANSWER : C

Explanation - Required percentage= $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = $\frac{9 \times 5700}{8 \times 8550} \times 100$ % = 75%

2. ANSWER : B

Explanation - The percentage of candidates passed to candidates enrolled can be determined for each institute as under:

P = $\frac{18 % o f 5700}{22 % o f 8550} \times 100$ % = 54.55%

Q = $\frac{17 % o f 5700}{15 % o f 8550} \times 100$ % = 75.56%

R = $\frac{13 % o f 5700}{10 % o f 8550} \times 100$ % = 86.67%

S = $\frac{16 % o f 5700}{17 % o f 8550} \times 100$ % = 62.75%

T = $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = 75%

V= $\frac{15 % o f 5700}{12 % o f 8550} \times 100$ % = 83.33%

X= $\frac{12 % o f 5700}{16 % o f 8550} \times 100$ % = 50%

Highest of these is 86.67% corresponding to institute R.

3. ANSWER : C

Explanation - Required difference = [(16% + 18%) of 5700] - [(8% + 10%) of 8550]

= [(34% of 5700) - (18% of 8550)]

= (1938 - 1539)

= 399

4. ANSWER : B

Explanation - Candidates passed from institutes Q and R together = [(13% + 17%) of 5700] = 30% of 57000.

Candidates enrolled from institutes Q and R together = [(15% + 10%) of 8550] = 25% of 8550.

Required Percentage = $\frac{30 % o f 5700}{25 % o f 8550} \times 100$ % = 80%

5. ANSWER : C

Explanation - Required ratio = $\frac{18 % o f 5700}{22 % o f 8550}$ = 6/11

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Subject: Pie Charts - Quantitative Aptitude - Data Interpretation

39 11672

The following line graph gives the ratio of the amounts of imports by a company to the amount of exports from that company over the period from 1995 to 2001.

Ratio of Value of Imports to Exports by a Company Over the Years.

1. If the imports in 1998 was Rs. 250 crores and the total exports in the years 1998 and 1999 together was Rs. 500 crores, then the imports in 1999 was ?

A. Rs. 250 cr B. Rs. 300 cr C. Rs. 357 cr D. Rs. 420 cr

2. The imports were minimum proportionate to the exports of the company in the year ?

A. 1995 B. 1996 C. 1997 D. 2000

3. What was the percentage increase in imports from 1997 to 1998 ?

A. 72 B. 56 C. 28 D. Data Inadequate

4. If the imports of the company in 1996 was Rs. 272 crores, the exports from the company in 1996 was ?

A. Rs. 370 cr B. Rs. 320 cr C. Rs. 280 cr D. Rs. 275 cr

5. In how many of the given years were the exports more than the imports ?

A. 1 B. 2 C. 3 D. 4

Answer

1. ANSWER : D

Explanation - The ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively.

Let the exports in the year 1999 = Rs. x crores.

Then, the exports in the year 1998 = Rs. (500 - x) crores.

$\frac{250}{500 - x} = 1.25 = > x = 300 crores$ [ Using ratio for 1998 ]

Thus, the exports in the year 1999 = Rs. 300 crores.

Let the imports in the year 1999 = Rs. y crores.

Then, Imports in the year 1999 = $\frac{y}{300} = 1.4 = > y = 420$ = Rs. 420 crores.

2. ANSWER : C

Explanation - The imports are minimum proportionate to the exports implies that the ratio of the value of imports to exports has the minimum value.

Now, this ratio has a minimum value 0.35 in 1997, i.e., the imports are minimum proportionate to the exports in 1997.

3. ANSWER : D

Explanation - The graph gives only the ratio of imports to exports for different years. To find the percentage increase in imports from 1997 to 1998, we require more details such as the value of imports or exports during these years.

Hence, the data is inadequate to answer this question.

4. ANSWER : B

Explanation - Ratio of imports to exports in the year 1996 = 0.85.

Let the exports in 1996 = Rs. x crores.

Then , $\frac{272}{x} = 0.85 = > x = 320$

Exports in 1996 = Rs. 320 crores.

5. ANSWER : D

Explanation - The exports are more than the imports imply that the ratio of value of imports to exports is less than 1.Now, this ratio is less than 1 in years 1995, 1996, 1997 and 2000.

Thus, there are four such years.

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Subject: Line Charts - Quantitative Aptitude - Data Interpretation Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

38 10300

The following pie chart shows the amount of subscriptions generated for India Bonds from different categories of investors.

1. In the corporate sector, approximately how many degrees should be there in the central angle ?

A. 120 B. 121 C. 122 D. 123

2. If the investment by NRI's are Rs 4,000 crore, then the investments by corporate houses and FII's tog ether is:

A. 24,000 cr B. 24,363 cr C. 25,423 cr D. 25,643 cr

3. What percentage of the total investment is coming from FII's and NRI's ?

A. 33% B. 11% C. 44% D. 22%

4. If the total investment other than by FII and corporate houses is Rs 335,000 crore, then the investment by NRI's and Offshore funds will be (approximately) ?

A. 274,100 B. 285,600 C. 293,000 D. Cannot be determined

5. If the total investment flows from FII's were to be doubled in the next year and the investment flows from all other sources had remained constant at their existing levels for this year, then what would be the proportion of FII investment in the total investment into India Bonds next year (in US $ millions) ?

A. 40% B. 50% C. 60% D. 70%

Answer

1. ANSWER : C

Explanation - 34 x 3.6 = 122.4 (since 1% = 3.6 degrees)

2. ANSWER : B

Explanation - (67/11) x 4000 = 24 363.6364

3. ANSWER : C

Explanation - (33 + 11) = 44

4. ANSWER : A

Explanation - Investment other than NRI and corporate houses is 33% = 335000. Also, investment by offshore funds and NRI's is equal to 27%.

Hence, (27 x 335000)/33 = 274 090.909

5. ANSWER : B

Explanation - FII's currently account for 33 out of 100.

If their value is doubled and all other investments are kept constant then their new value would be 66 out of 133 = approximately equal to 50%

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Subject: Pie Charts - Quantitative Aptitude - Data Interpretation

35 9722

Study the following graph carefully and answer the questions that follow:

Water level of four major Rivers (in meters) in four different Months

1. what was the respective ratio between the level of River - C in September and the water level of River - B in June?

1. 91 : 101 2. 94 : 101 3. 51 : 103 4. None of these

2. If the danger level of all the four rivers is above 215 m, which river has not crossed the danger level in August but has crossed the danger level in July ?

1. River - A 2. River - B 3. River - C 4. River - D

3. What is the average water level of River - A in all the four months together ?

1. 224.50 m 2. 212.25 m 3. 210.75 m 4. 222.25 m

4. In which river and in which month respectively the water level is highest ?

1. River - C in August 2. River - D in September 3. River - B in July 4. River - D in August

5. If the water level of River - A in July is decreased by 20 percent, then what will be the water level of River - A in July ?

1. 156 m 2. 162 m 3. 164 m 4. 152 m

Answer

1. Answer : 4

Explanation : The water level of River-C in September = 184 and water level of River-B in June = 202

Required ratio = 184 : 202 => 92 : 101

2. Answer : 2

3. Answer : 3

Explanation : Average water level of River-A in all months = $\frac{196 + 205 + 230 + 212}{4}$ = 210.75 m

4. Answer : 4

5. Answer : 3

Explanation : Water level of River-A in July after decreasing = $205 \times \frac{80}{100}$ = 41 x 4 = 164m

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Subject: Bar Charts - Quantitative Aptitude - Data Interpretation

13 8139

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