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 Problems on Ages Questions

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Q:

Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev?

A) 12 B) 14
C) 22 D) 10
 
Answer & Explanation Answer: D) 10

Explanation:

Let Rajeev's present age be  x years.

Rajeev's age after 15 years = (x + 15) years.

Rajeev's age 5 years back = (x - 5) years

Then ATQ, 

x + 15 = 5 (x - 5)

x + 15 = 5x - 25

=> x = 10

 

Hence, Rajeev's present age = x = 10 years.

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Q:

What is the age of Teja?

A: Four years ago, Raju was as old as Teja is at present.

B: Sita’s present age is two times of Raju’s present age.

C: The average age of Teja and Sita is 19 years.

A) Any two statements are sufficient to give answer B) Only C is sufficient
C) All of three statements are necessary to give answer D) Even using all the three statements answer cannot be found
 
Answer & Explanation Answer: C) All of three statements are necessary to give answer

Explanation:

From the given statements A, B & C

Let the present age of Teja = P

Raju present age = P + 4

Sita's present age = 2(P + 4)

Average of ages of Sita & Teja = 19

=> (2P + 8 + P)/2 = 19

= 3P + 8 = 38

=> P = 30/3 = 10

Hence, the present age of Teja = P = 10 yrs.

 

Therefore, by using all the three statements A, B & C we can find the age of Teja.

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Q:

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence.

Answer

Given that, A+B = 60  and A = 2B.


Solving, We get A = 40, B = 20.


Five years their ages will be 45 and 25, so the sum of their ages will be 70.


 

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Subject: Problems on Ages - Quantitative Aptitude - Arithmetic Ability

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Q:

The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class ?

A) 1:3 B) 2:3
C) 3:2 D) 3:1
 
Answer & Explanation Answer: B) 2:3

Explanation:

Let number of boys = x  , Let number of girls = y
Total numbers of students = x + y
(x + y) × 15.8 = 16.4x + 15.4y
0.6x = 0.4y
x/y = 0.4/0.6 = 2/3

 

 Ratio of boys and girls in the class is 2:3

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Q:

When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ?

A) 50 yrs B) 60 yrs
C) 70 yrs D) 65 yrs
 
Answer & Explanation Answer: B) 60 yrs

Explanation:

Let the Father be x years when he died

Average Age 10 years ago be A

Total Age 10 years ago = 6*A

Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60

Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0

(6A +60 - x)/6 = 6A/6
=> A + 10 -(x/6) = A
=> x/6 = 10
=> x = 60

Therefore we can conclude that the father was 60 years old when he died.

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Q:

Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :

A) 19 years B) 17 years
C) 15 years D) data inadequate
 
Answer & Explanation Answer: D) data inadequate

Explanation:

Let Meena’s age = A.
Then Sivagami’s age = A + 2
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.

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Q:

The ages of Krish and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:

A) 10 B) 13
C) 15 D) 18
 
Answer & Explanation Answer: C) 15

Explanation:

Krish’s age = 3A and Vaibhav’s age = 5A


(3A+9)/(5A+9) = 3/4


=> 4 (3A + 9) = 3 (5A + 9)


=> A = 3


Therefore, Vaibhav’s age = 15 years.

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Q:

A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present ?

A) 36 yrs B) 38 yrs
C) 40 yrs D) 42 yrs
 
Answer & Explanation Answer: C) 40 yrs

Explanation:

Let the mother's present age be x years.

Then, the person's present age = 2/5 x years.

(2x/5 + 8) = 1/2 (x + 8)

2(2x + 40) = 5(x + 8) => x = 40.

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