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 Problems on Ages Questions

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Q:

The age of a person is thrice the total ages of his 2 daughters. 0.5 decades hence, his age will be twice of the total ages of his daughters. Then what is the father’s current age? [0.5 Decades = 5 Years]

A) 35 years B) 40 years
C) 45 years D) 47 years
 
Answer & Explanation Answer: C) 45 years

Explanation:

Let, Total of current ages of the 2 daughters is A years.
Then, father’s current age = 3A years.
(3A + 5) = 2 (A +10)
3A + 5 = 2A + 20
A = 15
Therefore, father’s current age = 45 years.

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Filed Under: Problems on Ages - Quantitative Aptitude - Arithmetic Ability

27 12016
Q:

Proportion of Yuvaraj’s age to Ganguly’s age is 4:3. Yuvaraj willl be 26 years old after 6 years. What is the age of Ganguly now ?

A) 17 years B) 15 years
C) 19 years D) 12 years
 
Answer & Explanation Answer: B) 15 years

Explanation:

Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
A = 5
Current age of Ganguly = 3A
=> 3 x 5 = 15 years

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Filed Under: Problems on Ages - Quantitative Aptitude - Arithmetic Ability

22 11936
Q:

The Average age of 12 men is decreased by one year when two of them having ages 28 years and 32 years are replaced by two women of same age . The age of a women is?

Answer

Suppose age of each women be W and average age of 12 men be x



  


Hence , each woman's age = 24 years

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Subject: Problems on Ages - Quantitative Aptitude - Arithmetic Ability

37 11898
Q:

If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,

A) 30 B) 38
C) 40 D) 41
 
Answer & Explanation Answer: C) 40

Explanation:

Let daughter’s age = A and mother’s age = B
Given: 2A+B = 70 and A+2B = 95
Solving B, we will get B = 40.

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Filed Under: Problems on Ages - Quantitative Aptitude - Arithmetic Ability

42 11688
Q:

Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ?

A) 17 years B) 13 years
C) 14 years D) 16 years
 
Answer & Explanation Answer: B) 13 years

Explanation:

Given R + S + M + D = 76

=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8

=> Let the ratio = x

=> M+7 = 5x

=> M = 5x-7

=> R = 7x-7

=> S = 6x-7

=> D = 8x-7

=> R + S + M + D = 76

=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76

=> 26x - 28 = 76

=> 26x = 104

=> x = 4

=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.

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Filed Under: Problems on Ages - Quantitative Aptitude - Arithmetic Ability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

20 11549
Q:

The average age of 80 boys in a class is 15. The average age of group of 15 boys in the class is 16 and the average of another 25 boys in the class is 14. What is the average age of the remaining boys in the class ?

A) 12.24 yrs B) 13.25 yrs
C) 16 yrs D) 15.25 yrs
 
Answer & Explanation Answer: D) 15.25 yrs

Explanation:

Total ages of 80 boys = 15 x 80 = 1200 yrs.
Total age of 16 boys = 15 x 16 = 240 yrs
Total age of 25 boys = 14 x 25 = 350 yrs.
Average age of remaining boys = 1200 - (240+350) / 80 - (25+15) = 610/41 = 15.25 yrs.

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Filed Under: Problems on Ages - Quantitative Aptitude - Arithmetic Ability
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

11 11451
Q:

0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]

A) 8:1 B) 10:2
C) 11:4 D) 13:4
 
Answer & Explanation Answer: D) 13:4

Explanation:

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9  => A = 3

 

Needed Ratio = (4A + 1) : (A + 1) = 13 : 4

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21 11356
Q:

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child ?

A) 4 B) 8
C) 10 D) None
 
Answer & Explanation Answer: A) 4

Explanation:

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12. 

 

We know that the sum of their ages is 50 .

 

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

 

=>  x= 4

 

 The youngest child is 4 years old.

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Filed Under: Problems on Ages - Quantitative Aptitude - Arithmetic Ability

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