A train runs through cities A, B, C, D, E, F, G and H. The line graph indicates the time schedule of the train including times of arrival and departure. 

1. Answer : 4

Explanation : Required ratio = $\frac{10+2+5}{10+15+10}=\frac{17}{35}\approx \frac{1}{2}=1:2$ 

2. Answer : 1

Explanation : 

A to B Speed =$\frac{140\times 3}{5}$  = 84  

B to C Speed = $\frac{91\times 3}{4}$ = 68.25 

C to D Speed = $\frac{149\times 60}{103}$ = 86.796  

D to E Speed = $\frac{88\times 3}{4}$ = 66  

E to F Speed =  $\frac{106\times 4}{5}$= 84.8  

F to G Speed = $\frac{176}{2}$ = 88  

G to h Speed =  $\frac{110\times 4}{5}$= 88  

Average speed of entire trip = $\frac{84+68.25+86.796+66+84.8+88+88}{7}$ =80.83 

3. Answer : 3 

Explanation :  Total half time = 10 + 2 + 5 + 10 + 15 + 10 = 52 

Total half time, if the train stops at each city for 50% more=$52\times \frac{150}{100}$=78 

Train will arrive at city H after departing from city A = 18.25 + (78 - 52 )=18.25 + 26=18.51

4. Answer : 2 

 Explanation : Average speed = $\frac{84+68.25+86.796+66+84.8+88+88}{7}$=80.83=81 km/hr

5. Answer : 1 

Explanation :  Required percentage of time = $\frac{1.40+1.20+1.43+1.20+1.15+2+1.15}{18.25-7}\times 100$= $\frac{10.23}{11.25}\times 100$ = 91.8 %

1. Answer : 4

Explanation : Required ratio = 

2. Answer : 1

Explanation : A to B Speed =  = 84

B to C Speed =  = 68.25

C to D Speed =  = 86.796

D to E Speed =  = 66

E to F Speed =  = 84.8

F to G Speed =  = 88

G to h Speed =  = 88

Average speed of entire trip =  =80.83

3. Answer : 3

Explanation :  Total half time = 10 + 2 + 5 + 10 + 15 + 10 = 52

Total half time, if the train stops at each city for 50% more =  = 78

Train will arrive at city H after departing from city A = 18.25 + (78 - 52 ) = 18.25 + 26 = 18.51

4. Answer : 2

Explanation : Average speed =  = 80.83 = 81 km/hr

5. Answer : 1

Explanation :  Required percentage of time = 

= 

= 91.8 %